sin(cos^(-1)(x)) = sqrt(1-x^2) Let's draw a right triangle with an angle of a = cos^(-1)(x). As we know cos(a) = x = x/1 we can label the adjacent leg as x and the hypotenuse as 1. The Pythagorean theorem then allows us to solve for the second leg as sqrt(1-x^2). With this, we can now find sin(cos^(-1)(x)) as the quotient of the opposite leg and the hypotenuse. sin(cos^(-1)(x)) = sin(a) = sqrt(1-x^2)/1 = sqrt(1-x^2)
6. Simplify :cos−1(53cosx+54sinx). 7. write in the simplest
Solution: Simplify, [sinx/(1-cosx)]-[(1+cosx)/sinx]
ANSWERED] Simplify. sin x/1 + cos x +1 + cos x sin x ___ - Kunduz
Hey I just googled this set of really useful inverse trig
Solved Simplify sin (x + y)/sin x cos y = A. 1 B. sin y +
7.1: Simplifying Trigonometric Expressions with Identities
Find the value of the expression sin[cot^{-1}(cos(tan^{-1}1))]
Write an algebraic expression for cos(sin^-1 x), cosine of inverse
sin(cos^-1(u))